7m^2-6=19m

Solution for 7m^2-6=19m equation:

7m^2-6=19m

We move all terms to the left:

7m^2-6-(19m)=0

a = 7; b = -19; c = -6;
Δ = b2-4ac
Δ = -192-4·7·(-6)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-23}{2*7}=\frac{-4}{14}
=-2/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+23}{2*7}=\frac{42}{14}
=3
$